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Moist Air Process Enthalpy and Water Change

Calculate the change in moist-air enthalpy flow and water-vapour flow from inlet and outlet conditions and dry-air mass flow.

Inputs

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Result

Air-side enthalpy flow change: — kW

Air-side water-vapour flow change: — kg/s

A positive result means an increase from inlet to outlet; negative means a decrease. Water change is the net change in air-side water vapour.

Equations

ΔḢ = ṁda(hout − hin)
Δṁw = ṁda(wout − win)

Use h in kJ/kg dry air and w in kg water vapour/kg dry air. Results are kW and kg/s respectively.

Applicability

Steady state with the same dry-air mass flow at inlet and outlet; humidity ratio and enthalpy are per unit mass of dry air, and both enthalpies must use the same reference state. Neglect air kinetic-energy effects; the user must verify that inputs represent valid moist-air states.

This tool does not split enthalpy change into sensible and latent components or infer condensation from moisture removal; dehumidification may occur by different processes. Enthalpy carried by injected water, steam or drainage and heat losses may make the equipment's external heating or cooling duty differ from the air-side enthalpy change.

Worked example

For 1 kg/s dry air, inlet to outlet enthalpy 30 → 60 kJ/kg dry air and humidity ratio 8 → 12 g/kg dry air: enthalpy change is +30 kW and air-side water-vapour change is +0.004 kg/s.

For engineering estimates; verify equipment loads against complete mass and energy balances, operating conditions and applicable standards.